S3 : Conception et Programmation Objet Avancées
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- Attention pensez au rendu de fin de module
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This is an old revision of the document!
Objectifs = appréhender les tests par le jeu
Vous formez des groupes de 2 ou 3 étudiants. Une seule machine connectée à la session, cf. suite.
Plus : L'IDE est extrêmement simple : test=sauvegarder les codes, gestion de version, exécution automatique, etc. Sur le dashboard, on peut voir l'avancé de tous les groupes.
Défaut : L'IDE est extrêmement simple : pas d’auto completion, pas d’import, erreur debuggable par console java (pas d’aide de l’IDE)….
pouvez tenter de nouveaux codes si la structure première ne passe pas.
Top…. Toutes les 10mn, celui qui programme change. C'est OBLIGATOIRE !
Un nouveau jeu de tests vous est donné…(Comment???) Vous vérifiez qu'il passe, sinon… on recommence !
Vous corrigez, modifiez… Puis vous nous envoyez le .tgz obtenu par download
Vous amorcez le TD suivant
To try and encourage more sales of the 5 different Harry Potter books they sell, a bookshop has decided to offer discounts of multiple-book purchases. One copy of any of the five books costs 8 EUR. If, however, you buy two different books, you get a 5% discount on those two books. If you buy 3 different books, you get a 10% discount. If you buy 4 different books, you get a 20% discount. If you go the whole hog, and buy all 5, you get a huge 25% discount. Note that if you buy, say, four books, of which 3 are different titles, you get a 10% discount on the 3 that form part of a set, but the fourth book still costs 8 EUR. Your mission is to write a piece of code to calculate the price of any conceivable shopping basket (containing only Harry Potter books), giving as big a discount as possible. For example, how much does this basket of books cost? 2 copies of the first book 2 copies of the second book 2 copies of the third book 1 copy of the fourth book 1 copy of the fifth book One way of group these 8 books is: 1 group of 5 --> 25% discount (1st,2nd,3rd,4th,5th) +1 group of 3 --> 10% discount (1st,2nd,3rd) This would give a total of 5 books at a 25% discount +3 books at a 10% discount Giving 5 x (8 - 2.00) == 5 x 6.00 == 30.00 +3 x (8 - 0.80) == 3 x 7.20 == 21.60 For a total of 51.60 However, a different way to group these 8 books is: 1 group of 4 books --> 20% discount (1st,2nd,3rd,4th) +1 group of 4 books --> 20% discount (1st,2nd,3rd,5th) This would give a total of 4 books at a 20% discount +4 books at a 20% discount Giving 4 x (8-1.60) == 4 x 6.40 == 25.60 +4 x (8-1.60) == 4 x 6.40 == 25.60 For a total of 51.20 And 51.20 is the price with the biggest discount.